import math
def exact_prime_factor_count(n):
"""
>>> exact_prime_factor_count(51242183)
3
"""
count = 0
if n % 2 == 0:
count += 1
while n % 2 == 0:
n = int(n / 2)
i = 3
while i <= int(math.sqrt(n)):
if n % i == 0:
count += 1
while n % i == 0:
n = int(n / i)
i = i + 2
if n > 2:
count += 1
return count
if __name__ == "__main__":
n = 51242183
print(f"The number of distinct prime factors is/are {exact_prime_factor_count(n)}")
print(f"The value of log(log(n)) is {math.log(math.log(n)):.4f}")
"""
The number of distinct prime factors is/are 3
The value of log(log(n)) is 2.8765
"""