p

```
#!/usr/local/bin/python3
"""
Problem Description: Given two binary tree, return the merged tree.
The rule for merging is that if two nodes overlap, then put the value sum of
both nodes to the new value of the merged node. Otherwise, the NOT null node
will be used as the node of new tree.
"""
from __future__ import annotations
class Node:
"""
A binary node has value variable and pointers to its left and right node.
"""
def __init__(self, value: int = 0) -> None:
self.value = value
self.left: Node | None = None
self.right: Node | None = None
def merge_two_binary_trees(tree1: Node | None, tree2: Node | None) -> Node | None:
"""
Returns root node of the merged tree.
>>> tree1 = Node(5)
>>> tree1.left = Node(6)
>>> tree1.right = Node(7)
>>> tree1.left.left = Node(2)
>>> tree2 = Node(4)
>>> tree2.left = Node(5)
>>> tree2.right = Node(8)
>>> tree2.left.right = Node(1)
>>> tree2.right.right = Node(4)
>>> merged_tree = merge_two_binary_trees(tree1, tree2)
>>> print_preorder(merged_tree)
9
11
2
1
15
4
"""
if tree1 is None:
return tree2
if tree2 is None:
return tree1
tree1.value = tree1.value + tree2.value
tree1.left = merge_two_binary_trees(tree1.left, tree2.left)
tree1.right = merge_two_binary_trees(tree1.right, tree2.right)
return tree1
def print_preorder(root: Node | None) -> None:
"""
Print pre-order traversal of the tree.
>>> root = Node(1)
>>> root.left = Node(2)
>>> root.right = Node(3)
>>> print_preorder(root)
1
2
3
>>> print_preorder(root.right)
3
"""
if root:
print(root.value)
print_preorder(root.left)
print_preorder(root.right)
if __name__ == "__main__":
tree1 = Node(1)
tree1.left = Node(2)
tree1.right = Node(3)
tree1.left.left = Node(4)
tree2 = Node(2)
tree2.left = Node(4)
tree2.right = Node(6)
tree2.left.right = Node(9)
tree2.right.right = Node(5)
print("Tree1 is: ")
print_preorder(tree1)
print("Tree2 is: ")
print_preorder(tree2)
merged_tree = merge_two_binary_trees(tree1, tree2)
print("Merged Tree is: ")
print_preorder(merged_tree)
```