S

A

S

a

```
/**
* @file
*
* @brief Calculates the [Cross Product](https://en.wikipedia.org/wiki/Cross_product) and the magnitude of two mathematical 3D vectors.
*
*
* @details Cross Product of two vectors gives a vector.
* Direction Ratios of a vector are the numeric parts of the given vector. They are the tree parts of the
* vector which determine the magnitude (value) of the vector.
* The method of finding a cross product is the same as finding the determinant of an order 3 matrix consisting
* of the first row with unit vectors of magnitude 1, the second row with the direction ratios of the
* first vector and the third row with the direction ratios of the second vector.
* The magnitude of a vector is it's value expressed as a number.
* Let the direction ratios of the first vector, P be: a, b, c
* Let the direction ratios of the second vector, Q be: x, y, z
* Therefore the calculation for the cross product can be arranged as:
*
* ```
* P x Q:
* 1 1 1
* a b c
* x y z
* ```
*
* The direction ratios (DR) are calculated as follows:
* 1st DR, J: (b * z) - (c * y)
* 2nd DR, A: -((a * z) - (c * x))
* 3rd DR, N: (a * y) - (b * x)
*
* Therefore, the direction ratios of the cross product are: J, A, N
* The following C++ Program calculates the direction ratios of the cross products of two vector.
* The program uses a function, cross() for doing so.
* The direction ratios for the first and the second vector has to be passed one by one seperated by a space character.
*
* Magnitude of a vector is the square root of the sum of the squares of the direction ratios.
*
* ### Example:
* An example of a running instance of the executable program:
*
* Pass the first Vector: 1 2 3
* Pass the second Vector: 4 5 6
* The cross product is: -3 6 -3
* Magnitude: 7.34847
*
* @author [Shreyas Sable](https://github.com/Shreyas-OwO)
*/
#include <iostream>
#include <array>
#include <cmath>
#include <cassert>
/**
* @namespace math
* @brief Math algorithms
*/
namespace math {
/**
* @namespace vector_cross
* @brief Functions for Vector Cross Product algorithms
*/
namespace vector_cross {
/**
* @brief Function to calculate the cross product of the passed arrays containing the direction ratios of the two mathematical vectors.
* @param A contains the direction ratios of the first mathematical vector.
* @param B contains the direction ration of the second mathematical vector.
* @returns the direction ratios of the cross product.
*/
std::array<double, 3> cross(const std::array<double, 3> &A, const std::array<double, 3> &B) {
std::array<double, 3> product;
/// Performs the cross product as shown in @algorithm.
product[0] = (A[1] * B[2]) - (A[2] * B[1]);
product[1] = -((A[0] * B[2]) - (A[2] * B[0]));
product[2] = (A[0] * B[1]) - (A[1] * B[0]);
return product;
}
/**
* @brief Calculates the magnitude of the mathematical vector from it's direction ratios.
* @param vec an array containing the direction ratios of a mathematical vector.
* @returns type: double description: the magnitude of the mathematical vector from the given direction ratios.
*/
double mag(const std::array<double, 3> &vec) {
double magnitude = sqrt((vec[0] * vec[0]) + (vec[1] * vec[1]) + (vec[2] * vec[2]));
return magnitude;
}
} /// namespace vector_cross
} /// namespace math
/**
* @brief test function.
* @details test the cross() and the mag() functions.
*/
static void test() {
/// Tests the cross() function.
std::array<double, 3> t_vec = math::vector_cross::cross({1, 2, 3}, {4, 5, 6});
assert(t_vec[0] == -3 && t_vec[1] == 6 && t_vec[2] == -3);
/// Tests the mag() function.
double t_mag = math::vector_cross::mag({6, 8, 0});
assert(t_mag == 10);
}
/**
* @brief Main Function
* @details Asks the user to enter the direction ratios for each of the two mathematical vectors using std::cin
* @returns 0 on exit
*/
int main() {
/// Tests the functions with sample input before asking for user input.
test();
std::array<double, 3> vec1;
std::array<double, 3> vec2;
/// Gets the values for the first vector.
std::cout << "\nPass the first Vector: ";
std::cin >> vec1[0] >> vec1[1] >> vec1[2];
/// Gets the values for the second vector.
std::cout << "\nPass the second Vector: ";
std::cin >> vec2[0] >> vec2[1] >> vec2[2];
/// Displays the output out.
std::array<double, 3> product = math::vector_cross::cross(vec1, vec2);
std::cout << "\nThe cross product is: " << product[0] << " " << product[1] << " " << product[2] << std::endl;
/// Displays the magnitude of the cross product.
std::cout << "Magnitude: " << math::vector_cross::mag(product) << "\n" << std::endl;
return 0;
}
```