The Algorithms logo
The Algorithms
Acerca deDonar

Pow

A
l
/**
 * @function powLinear
 * @description - The powLinear function is a power function with Linear O(n) complexity
 * @param {number} base
 * @param {number} exponent
 * @returns {number}
 * @example - powLinear(2, 2) => 4 --> 2 * 2
 * @example - powLinear(3, 3) => 27 --> 3 * 3 * 3
 */
const powLinear = (base, exponent) => {
  if (exponent < 0) {
    base = 1 / base
    exponent = -exponent
  }

  let result = 1

  while (exponent--) {
    // Break the execution while the exponent will 0
    result *= base
  }

  return result
}

/**
 * @function powFaster
 * @description - The powFaster function is a power function with O(logN) complexity
 * @param {number} base
 * @param {number} exponent
 * @returns {number}
 * @example - powFaster(2, 2) => 4 --> 2 * 2
 * @example - powFaster(3, 3) => 27 --> 3 * 3 * 3
 */
const powFaster = (base, exponent) => {
  if (exponent < 2) {
    // explanation below - 1
    return base && ([1, base][exponent] || powFaster(1 / base, -exponent))
  }

  if (exponent & 1) {
    // if the existing exponent is odd
    return base * powFaster(base * base, exponent >> 1) // explanation below - 2
  }

  return powFaster(base * base, exponent / 2)
}

/**
 * 1 - Magic of short circuit evaluation (&&, ||)
 * if the base is 0 then it returns 0 cause 0 is falsy
 * if the base is not 0 then it's must be truthy. after that, it will be executed the right portion of the && (AND) operator
 * Now it checks the exponent by the help array index, is it 0 or 1.
 * if the exponent is not 0 or 1 it's definitely less than 0, and a negative number is not a valid index number so it returns "undefined"
 * if the expression is undefined mean -> falsy, the || (OR) operator evaluates the right portion that is a recursive function.
 */

/**
 * 2 - Play with right shift bitwise operator (>>)
 * right shift with any odd numbers it returns the floor number instead of float.
 * E.g. if the number is 5, after right shifting with 1 it's will give us 2, not 2.5
 * cause the right shift formula is --> x >> y = |x| / 2^y
 */

export { powLinear, powFaster }