package com.thealgorithms.dynamicprogramming;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* The AssignmentUsingBitmask class is used to calculate the total number of ways
* tasks can be distributed among people, given specific constraints on who can perform which tasks.
* The approach uses bitmasking and dynamic programming to efficiently solve the problem.
*
* @author Hardvan
*/
public final class AssignmentUsingBitmask {
private final int totalTasks;
private final int[][] dp;
private final List<List<Integer>> task;
private final int finalMask;
/**
* Constructor for the AssignmentUsingBitmask class.
*
* @param taskPerformed a list of lists, where each inner list contains the tasks that a person can perform.
* @param total the total number of tasks.
*/
public AssignmentUsingBitmask(List<List<Integer>> taskPerformed, int total) {
this.totalTasks = total;
this.dp = new int[1 << taskPerformed.size()][total + 1];
for (int[] row : dp) {
Arrays.fill(row, -1);
}
this.task = new ArrayList<>(totalTasks + 1);
for (int i = 0; i <= totalTasks; i++) {
this.task.add(new ArrayList<>());
}
// Final mask to check if all persons are included
this.finalMask = (1 << taskPerformed.size()) - 1;
// Fill the task list
for (int i = 0; i < taskPerformed.size(); i++) {
for (int j : taskPerformed.get(i)) {
this.task.get(j).add(i);
}
}
}
/**
* Counts the ways to assign tasks until the given task number with the specified mask.
*
* @param mask the bitmask representing the current state of assignments.
* @param taskNo the current task number being processed.
* @return the number of ways to assign tasks.
*/
private int countWaysUntil(int mask, int taskNo) {
if (mask == finalMask) {
return 1;
}
if (taskNo > totalTasks) {
return 0;
}
if (dp[mask][taskNo] != -1) {
return dp[mask][taskNo];
}
int totalWays = countWaysUntil(mask, taskNo + 1);
// Assign tasks to all possible persons
for (int p : task.get(taskNo)) {
// If the person is already assigned a task
if ((mask & (1 << p)) != 0) {
continue;
}
totalWays += countWaysUntil(mask | (1 << p), taskNo + 1);
}
dp[mask][taskNo] = totalWays;
return dp[mask][taskNo];
}
/**
* Counts the total number of ways to distribute tasks among persons.
*
* @return the total number of ways to distribute tasks.
*/
public int countNoOfWays() {
return countWaysUntil(0, 1);
}
}