package com.thealgorithms.bitmanipulation;
/**
* A utility class to swap every pair of adjacent bits in a given integer.
* This operation shifts the even-positioned bits to odd positions and vice versa.
*
* Example:
* - Input: 2 (binary: `10`) → Output: 1 (binary: `01`)
* - Input: 43 (binary: `101011`) → Output: 23 (binary: `010111`)
*
* **Explanation of the Algorithm:**
* 1. Mask even-positioned bits: Using `0xAAAAAAAA` (binary: `101010...`),
* which selects bits in even positions.
* 2. Mask odd-positioned bits: Using `0x55555555` (binary: `010101...`),
* which selects bits in odd positions.
* 3. Shift bits:
* - Right-shift even-positioned bits by 1 to move them to odd positions.
* - Left-shift odd-positioned bits by 1 to move them to even positions.
* 4. Combine both shifted results using bitwise OR (`|`) to produce the final result.
*
* Use Case: This algorithm can be useful in applications involving low-level bit manipulation,
* such as encoding, data compression, or cryptographic transformations.
*
* Time Complexity: O(1) (constant time, since operations are bitwise).
*
* Author: Lakshyajeet Singh Goyal (https://github.com/DarkMatter-999)
*/
public final class SwapAdjacentBits {
private SwapAdjacentBits() {
}
/**
* Swaps every pair of adjacent bits of a given integer.
* Steps:
* 1. Mask the even-positioned bits.
* 2. Mask the odd-positioned bits.
* 3. Shift the even bits to the right and the odd bits to the left.
* 4. Combine the shifted bits.
*
* @param num the integer whose bits are to be swapped
* @return the integer after swapping every pair of adjacent bits
*/
public static int swapAdjacentBits(int num) {
// mask the even bits (0xAAAAAAAA => 10101010...)
int evenBits = num & 0xAAAAAAAA;
// mask the odd bits (0x55555555 => 01010101...)
int oddBits = num & 0x55555555;
// right shift even bits and left shift odd bits
evenBits >>= 1;
oddBits <<= 1;
// combine shifted bits
return evenBits | oddBits;
}
}